OSGi™ Service Platform
Release 4 Version 4.2

org.osgi.framework
Interface ServiceReference

All Superinterfaces:
java.lang.Comparable

public interface ServiceReference
extends java.lang.Comparable

A reference to a service.

The Framework returns ServiceReference objects from the BundleContext.getServiceReference and BundleContext.getServiceReferences methods.

A ServiceReference object may be shared between bundles and can be used to examine the properties of the service and to get the service object.

Every service registered in the Framework has a unique ServiceRegistration object and may have multiple, distinct ServiceReference objects referring to it. ServiceReference objects associated with a ServiceRegistration object have the same hashCode and are considered equal (more specifically, their equals() method will return true when compared).

If the same service object is registered multiple times, ServiceReference objects associated with different ServiceRegistration objects are not equal.

See Also:
BundleContext.getServiceReference(java.lang.String), BundleContext.getServiceReferences(java.lang.String, java.lang.String), BundleContext.getService(org.osgi.framework.ServiceReference)
ThreadSafe

Method Summary
 int compareTo(java.lang.Object reference)
          Compares this ServiceReference with the specified ServiceReference for order.
 Bundle getBundle()
          Returns the bundle that registered the service referenced by this ServiceReference object.
 java.lang.Object getProperty(java.lang.String key)
          Returns the property value to which the specified property key is mapped in the properties Dictionary object of the service referenced by this ServiceReference object.
 java.lang.String[] getPropertyKeys()
          Returns an array of the keys in the properties Dictionary object of the service referenced by this ServiceReference object.
 Bundle[] getUsingBundles()
          Returns the bundles that are using the service referenced by this ServiceReference object.
 boolean isAssignableTo(Bundle bundle, java.lang.String className)
          Tests if the bundle that registered the service referenced by this ServiceReference and the specified bundle use the same source for the package of the specified class name.
 

Method Detail

getProperty

java.lang.Object getProperty(java.lang.String key)
Returns the property value to which the specified property key is mapped in the properties Dictionary object of the service referenced by this ServiceReference object.

Property keys are case-insensitive.

This method must continue to return property values after the service has been unregistered. This is so references to unregistered services (for example, ServiceReference objects stored in the log) can still be interrogated.

Parameters:
key - The property key.
Returns:
The property value to which the key is mapped; null if there is no property named after the key.

getPropertyKeys

java.lang.String[] getPropertyKeys()
Returns an array of the keys in the properties Dictionary object of the service referenced by this ServiceReference object.

This method will continue to return the keys after the service has been unregistered. This is so references to unregistered services (for example, ServiceReference objects stored in the log) can still be interrogated.

This method is case-preserving ; this means that every key in the returned array must have the same case as the corresponding key in the properties Dictionary that was passed to the BundleContext.registerService(String[],Object,Dictionary) or ServiceRegistration.setProperties(java.util.Dictionary) methods.

Returns:
An array of property keys.

getBundle

Bundle getBundle()
Returns the bundle that registered the service referenced by this ServiceReference object.

This method must return null when the service has been unregistered. This can be used to determine if the service has been unregistered.

Returns:
The bundle that registered the service referenced by this ServiceReference object; null if that service has already been unregistered.
See Also:
BundleContext.registerService(String[],Object,Dictionary)

getUsingBundles

Bundle[] getUsingBundles()
Returns the bundles that are using the service referenced by this ServiceReference object. Specifically, this method returns the bundles whose usage count for that service is greater than zero.

Returns:
An array of bundles whose usage count for the service referenced by this ServiceReference object is greater than zero; null if no bundles are currently using that service.
Since:
1.1

isAssignableTo

boolean isAssignableTo(Bundle bundle,
                       java.lang.String className)
Tests if the bundle that registered the service referenced by this ServiceReference and the specified bundle use the same source for the package of the specified class name.

This method performs the following checks:

  1. Get the package name from the specified class name.
  2. For the bundle that registered the service referenced by this ServiceReference (registrant bundle); find the source for the package. If no source is found then return true if the registrant bundle is equal to the specified bundle; otherwise return false.
  3. If the package source of the registrant bundle is equal to the package source of the specified bundle then return true; otherwise return false.

Parameters:
bundle - The Bundle object to check.
className - The class name to check.
Returns:
true if the bundle which registered the service referenced by this ServiceReference and the specified bundle use the same source for the package of the specified class name. Otherwise false is returned.
Throws:
java.lang.IllegalArgumentException - If the specified Bundle was not created by the same framework instance as this ServiceReference.
Since:
1.3

compareTo

int compareTo(java.lang.Object reference)
Compares this ServiceReference with the specified ServiceReference for order.

If this ServiceReference and the specified ServiceReference have the same service id they are equal. This ServiceReference is less than the specified ServiceReference if it has a lower service ranking and greater if it has a higher service ranking. Otherwise, if this ServiceReference and the specified ServiceReference have the same service ranking, this ServiceReference is less than the specified ServiceReference if it has a higher service id and greater if it has a lower service id.

Specified by:
compareTo in interface java.lang.Comparable
Parameters:
reference - The ServiceReference to be compared.
Returns:
Returns a negative integer, zero, or a positive integer if this ServiceReference is less than, equal to, or greater than the specified ServiceReference.
Throws:
java.lang.IllegalArgumentException - If the specified ServiceReference was not created by the same framework instance as this ServiceReference.
Since:
1.4

OSGi™ Service Platform
Release 4 Version 4.2

Copyright © OSGi Alliance (2000, 2010). All Rights Reserved. Licensed under the OSGi Specification License, Version 1.0